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Sodium has body centred packing. Distance between two nearest atoms is 3.7 Å. The lattice parameter is

1. 4.3 Å
2. 3.0 Å
3. 8.6 Å
4. 6.8 Å

Correct answer: 6.8 Å

Solution

In a body-centered cubic (BCC) lattice, the nearest neighbor distance is equal to half the body diagonal. The body diagonal is √3 times the lattice parameter (a). Thus, 3.7 Å = √3 * a / 2. Solving for a gives a = 6.8 Å.

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