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Let, the amount of the two in the mixture will become equal after t years. The amount of A₁, which remains after t years.

1. N₁ = N₀₁/(2^(t/20))
2. N₂ = N₀₂/(2^(t/10))
3. t/20 = t/10 - 2
4. t = 40 s

Correct answer: N₁ = N₀₁/(2^(t/20))

Solution

The formula for radioactive decay is N = N₀/(2^(t/T)), where T is the half-life. Option A correctly represents the remaining amount of A₁ after time t.

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