Exams › NEET › Physics

If the nucleus 27/13 Al has nuclear radius of about 3.6 fm, then 125/32 Te would have its radius approximately as:

1. 9.6 fm
2. 12.0 fm
3. 4.8 fm
4. 6.0 fm

Correct answer: 6.0 fm

Solution

The nuclear radius is proportional to the cube root of the mass number (A). Using the formula R = R₀A^(1/3), where R₀ is the proportionality constant, we calculate the radius of 125/32 Te relative to 27/13 Al. Since R₁/R₂ = (A₁/A₂)^(1/3), substituting A₁ = 125 and A₂ = 27 gives R₂ ≈ 6.0 fm.

Related NEET Physics questions

• Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be:
• If radius of the 27/13 Al nucleus is taken to be R_Al, then the radius of 125/53 Te nucleus is nearly:
• If the nuclear radius of 27/13 Al is 3.6 Fermi, the approximate nuclear radius of 64/29 Cu in Fermi is:
• The radius of germanium (Ge) nuclide is measured to be twice the radius of 9/4 Be. The number of nucleons in Ge are:
• The nuclei of which one of the following pairs of nuclei are isobars?
• A nucleus represented by the symbol A/Z X has:

⚔️ Practice NEET Physics free + battle 1v1 →