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When an X emits one α-particle then its atomic mass decreases by 4 units and atomic number by 2. Therefore, the new nucleus becomes m−4Y. But as it emits two β− particles, its atomic number increases by 2. Thus the resulting nucleus is m−4X.
- m−4X
- m−4Y
- m−2X
- m−2Y
Correct answer: m−4X
Solution
When an α-particle is emitted, the atomic mass decreases by 4 and the atomic number decreases by 2, forming m−4Y. Emission of two β− particles increases the atomic number by 2, bringing it back to the original element X. Thus, the resulting nucleus is m−4X.
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