Exams › NEET › Physics

N₁ = N₀e^(-λt), N₁ = 1/3N₀.

1. N₀/3 = N₀e^(-λt₂)
2. 1/3 = e^(-λt₂)
3. N₂ = 2/3N₀
4. N₁ = N₀e^(-λt)

Correct answer: 1/3 = e^(-λt₂)

Solution

The equation N₁ = N₀e^(-λt) represents radioactive decay. Substituting N₁ = 1/3N₀ into the equation gives 1/3 = e^(-λt), which matches option B.

Related NEET Physics questions

• Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be:
• If radius of the 27/13 Al nucleus is taken to be R_Al, then the radius of 125/53 Te nucleus is nearly:
• If the nuclear radius of 27/13 Al is 3.6 Fermi, the approximate nuclear radius of 64/29 Cu in Fermi is:
• The radius of germanium (Ge) nuclide is measured to be twice the radius of 9/4 Be. The number of nucleons in Ge are:
• If the nucleus 27/13 Al has nuclear radius of about 3.6 fm, then 125/32 Te would have its radius approximately as:
• The nuclei of which one of the following pairs of nuclei are isobars?

⚔️ Practice NEET Physics free + battle 1v1 →