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²H and ³H requires a and b amount of energies for their nucleons to be separated. ⁴He releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. Hence, Energy released = c - (a + b) = c - a - b

1. Binding energy per nucleon for fission products is higher relative to Binding energy per nucleon for parent nucleus, i.e., more masses are lost and are obtained as kinetic energy of fission products. So, the given ratio < 1.
2. B.E. per nucleon is smaller for lighter as well as heavier nucleus. But fusion reaction occurs for small mass number nuclei and fission reaction occurs for larger mass number nuclei to attain reaction binding energy per nucleon.
3. m₃ < (m₁ + m₂) (∵ m₁ + m₂ = m₃ + E) E = [m₁ + m₂ - m₃] c²
4. Mass defect = B.E / c²

Correct answer: Mass defect = B.E / c²

Solution

The mass defect is defined as the difference between the mass of the nucleons in a nucleus and the actual mass of the nucleus. This difference corresponds to the binding energy divided by c², as per Einstein's mass-energy equivalence.

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