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An element A decays into element C by a two step process A → B + He⁴ B → C + 2e⁻ Then

1. A and C are isotopes
2. A and C are isobars
3. A and B are isotopes
4. A and B are isobars

Correct answer: A and C are isobars

Solution

In the first step, A loses a helium nucleus (He⁴), reducing its mass number by 4 and atomic number by 2. In the second step, B undergoes beta decay, increasing its atomic number by 1. Thus, A and C have the same mass number but different atomic numbers, making them isobars.

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