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In a given reaction zX⁴ → z+1Y⁴ → z-1K⁴ → z-2L⁴ → z-4K⁴ Radioactive radiations are emitted in the sequence of

1. α, β, γ
2. γ, α, β
3. β, α, γ
4. γ, β, α

Correct answer: γ, β, α

Solution

The sequence of radioactive decay involves gamma (γ) emission first, which does not change the atomic number, followed by beta (β) emission, which increases the atomic number by 1, and finally alpha (α) emission, which decreases the atomic number by 2. This matches the given reaction sequence.

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