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What is the respective number of α and β-particles emitted in the following radioactive decay 90X90 → 168Y80?

1. 6 and 8
2. 6 and 6
3. 8 and 8
4. 8 and 6

Correct answer: 8 and 6

Solution

In the given decay, the atomic number decreases from 90 to 80, indicating the emission of 10 protons. Each α-particle reduces the atomic number by 2, so 10/2 = 5 α-particles are emitted. The mass number decreases from 90 to 168, a difference of 22. Each β-particle increases the atomic number by 1, so 6 β-particles are emitted to balance the change. Thus, the correct answer is 8 α-particles and 6 β-particles.

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