Exams › NEET › Physics

A deuteron strikes ₈O¹⁶ nucleus with subsequent emission of an alpha particle. Identify the nucleus so produced

1. ₃Li⁷
2. ₅B¹⁰
3. ₇N¹³
4. ₇N¹⁴

Correct answer: ₇N¹⁴

Solution

The reaction is: ²H + ₈O¹⁶ → ₄He² + ₇N¹⁴. By conserving both mass number and atomic number, the resulting nucleus is ₇N¹⁴.

Related NEET Physics questions

• Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be:
• If radius of the 27/13 Al nucleus is taken to be R_Al, then the radius of 125/53 Te nucleus is nearly:
• If the nuclear radius of 27/13 Al is 3.6 Fermi, the approximate nuclear radius of 64/29 Cu in Fermi is:
• The radius of germanium (Ge) nuclide is measured to be twice the radius of 9/4 Be. The number of nucleons in Ge are:
• If the nucleus 27/13 Al has nuclear radius of about 3.6 fm, then 125/32 Te would have its radius approximately as:
• The nuclei of which one of the following pairs of nuclei are isobars?

⚔️ Practice NEET Physics free + battle 1v1 →