Exams › NEET › Physics

The decay constant (λ) and the half-life (T) of a radioactive isotope are related as

1. λ = log₂ e / T
2. λ = 1 / log₂ 2T
3. λ = T / log₂ 2
4. λ = 2 / T

Correct answer: λ = log₂ e / T

Solution

The relationship between the decay constant (λ) and the half-life (T) is given by λ = ln(2) / T, where ln(2) is the natural logarithm of 2. Since log₂ e is equivalent to ln(2), the correct option is A.

Related NEET Physics questions

• Two nuclei have their mass numbers in the ratio of 1 : 3. The ratio of their nuclear densities would be:
• If radius of the 27/13 Al nucleus is taken to be R_Al, then the radius of 125/53 Te nucleus is nearly:
• If the nuclear radius of 27/13 Al is 3.6 Fermi, the approximate nuclear radius of 64/29 Cu in Fermi is:
• The radius of germanium (Ge) nuclide is measured to be twice the radius of 9/4 Be. The number of nucleons in Ge are:
• If the nucleus 27/13 Al has nuclear radius of about 3.6 fm, then 125/32 Te would have its radius approximately as:
• The nuclei of which one of the following pairs of nuclei are isobars?

⚔️ Practice NEET Physics free + battle 1v1 →