Correct answer: 60 days
The fraction of undecayed nuclei is given by N/N₀ = (1/2)^(t/T). For 1/3 decayed, N/N₀ = 2/3, and for 2/3 decayed, N/N₀ = 1/3. Solving for t₁ and t₂ using the half-life T = 50 days, we find t₁ = 50 log(3/2)/log(2) and t₂ = 50 log(3)/log(2). The difference t₂ - t₁ simplifies to 50 days.