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Energy released in the fission of a single ²³⁵U nucleus is 200 MeV. The fission rate of a ²³⁵U fuelled reactor operating at a power level of 5 W is:

1. 5 W
2. 1.56 × 10⁻¹⁶ s⁻¹
3. 1.56 × 10¹⁶ s⁻¹
4. 1.56 × 10¹⁷ s⁻¹

Correct answer: 1.56 × 10¹⁶ s⁻¹

Solution

The energy released per fission is 200 MeV, which is equivalent to 200 × 1.6 × 10⁻¹³ J. The power of the reactor is 5 W, so the fission rate is calculated as Power / Energy per fission = 5 / (200 × 1.6 × 10⁻¹³) = 1.56 × 10¹⁶ s⁻¹.

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