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Complete the equation for the following fission process: 92U²³⁵ → 38Sr⁹⁵ + ...

1. 54Xe¹⁴³ + 3 0n¹
2. 54Xe¹⁴⁵ + 3 0n¹
3. 54Xe¹⁴² + 0n¹
4. 54Xe¹⁴² + 4 0n¹

Correct answer: 54Xe¹⁴³ + 3 0n¹

Solution

In nuclear fission, the sum of mass numbers and atomic numbers must be conserved. For 92U²³⁵ splitting into 38Sr⁹⁵ and 54Xe¹⁴³, the remaining mass and atomic numbers match when 3 neutrons (3 0n¹) are emitted.

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