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The binding energy of deuteron is 2.2 MeV and that of 42He is 28 MeV. If two deuterons are fused to form one 42He, then the energy released is

1. 23.6 MeV
2. 19.2 MeV
3. 30.2 MeV
4. 25.8 MeV

Correct answer: 23.6 MeV

Solution

The binding energy of two deuterons is 2 × 2.2 MeV = 4.4 MeV. The binding energy of 42He is 28 MeV. The energy released during fusion is the difference: 28 MeV - 4.4 MeV = 23.6 MeV.

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