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The ratio of the radii of the nuclei ^17_8O and ^125_52Te is approximately

1. 6 : 10
2. 13 : 52
3. 40 : 177
4. 14 : 73

Correct answer: 40 : 177

Solution

The radius of a nucleus is proportional to the cube root of its mass number (A). For ^17_8O and ^125_52Te, the ratio of radii is approximately (17)^(1/3) : (125)^(1/3), which simplifies to about 40:177.

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