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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is (Given: 1 a.m.u = 931 MeV)

1. 267 MeV
2. 6.675 MeV
3. 13.35 MeV
4. 2.67 MeV

Correct answer: 13.35 MeV

Solution

The energy released per a.m.u. is calculated using Einstein's mass-energy equivalence, E = Δm × c². Here, Δm = 0.02866 a.m.u., and the energy equivalent of 1 a.m.u. is 931 MeV. Thus, energy per a.m.u. = 0.02866 × 931 = 13.35 MeV.

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