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When a uranium isotope ^235_92U is bombarded with a neutron, it generates ^89_36Kr, three neutrons and:

1. ^91_40Zr
2. ^101_36Kr
3. ^103_36Kr
4. ^144_56Ba

Correct answer: ^144_56Ba

Solution

The nuclear reaction must conserve both mass number and atomic number. The mass number of uranium (235) plus the neutron (1) equals 236. Subtracting the mass numbers of krypton (89) and three neutrons (3) leaves 144, which corresponds to barium. Similarly, the atomic number of uranium (92) minus krypton (36) and three neutrons (0) equals 56, which matches barium.

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