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The mass number of He is 4 and that for sulphur is 32. The radius of sulphur nuclei is larger than that of helium by

1. √8
2. 4
3. 2
4. 8

Correct answer: √8

Solution

The nuclear radius is proportional to the cube root of the mass number (A). For helium, A = 4, and for sulfur, A = 32. The ratio of their radii is (32/4)^(1/3) = 2^(3/3) = √8.

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