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The stable nucleus that has a radius half that of Fe^56 is

1. Li^7
2. Na^21
3. Si^16
4. Ca^40

Correct answer: Li^7

Solution

The radius of a nucleus is proportional to the cube root of its mass number (A). Since the radius of the stable nucleus is half that of Fe^56, its mass number should be approximately (1/8) of 56, which is close to 7. Thus, the correct answer is Li^7.

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