Exams › NEET › Physics

The total energy of electron in the ground state of hydrogen atom is −13.6 eV. The kinetic energy of an electron in the first excited state is

1. 6.8 eV
2. 13.6 eV
3. 1.7 eV
4. 3.4 eV

Correct answer: 3.4 eV

Solution

In the first excited state (n=2), the total energy of the electron is -3.4 eV. The kinetic energy is equal in magnitude to the total energy but positive, so it is 3.4 eV.

Related NEET Physics questions

• The ground state energy of H-atom 13.6 eV. The energy needed to ionize H-atom from its second excited state.
• To explain his theory, Bohr used
• The ionisation energy of hydrogen atom is 13.6 eV, the ionisation energy of helium atom would be
• For the wavelength λ = 975 Å, calculate the number of spectral lines emitted when an electron transitions from n = 4 to n = 1.
• The ratio of temperatures T₁/T₂ is proportional to the cube of the ratio of principal quantum numbers n₁/n₂. If n₁ = 2n₂, find the ratio T₁/T₂.
• According to the Rydberg formula, calculate the wavelength λ₁ for the transition from n = 4 to n = 3.

⚔️ Practice NEET Physics free + battle 1v1 →