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ExamsNEETPhysics

The ionization energy of the electron in the hydrogen atom in its ground state is 13.6 eV. The atoms are excited to higher energy levels to emit radiations of wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

  1. n = 3 to n = 1 states
  2. n = 2 to n = 1 states
  3. n = 4 to n = 3 states
  4. n = 3 to n = 2 states

Correct answer: n = 4 to n = 3 states

Solution

The maximum wavelength corresponds to the minimum energy difference between two levels. The transition from n = 4 to n = 3 has the smallest energy difference among the given options, leading to the maximum wavelength.

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