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The ratio of kinetic energy to the total energy of an electron in a Bohr orbit of the hydrogen atom, is:

1. 1 : 1
2. 1 : −1
3. 1 : −2
4. 2 : −1

Correct answer: 1 : −2

Solution

In the Bohr model of the hydrogen atom, the total energy (E) of the electron is equal to the negative of its kinetic energy (K), and the potential energy (U) is twice the total energy. Thus, K/E = 1 : -2.

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