Two conductors each of length $ 12 m $ lie parallel to each other in air. The centre to centre distance between the two conductors is $ 15 \times 10^{-2} m $ and the current in each conductor is $ 300 A $. The force in newton tending to pull the conductors together is:

Q: Two conductors each of length $ 12 m $ lie parallel to each other in air. The centre to centre distance between the two conductors is $ 15 \times 10^{-2} m $ and the current in each conductor is $ 300 A $. The force in newton tending to pull the conductors together is:

$ 1.44 N $. For two parallel conductors, the attractive force is proportional to $I_1 I_2 L / d$. Substituting the given values into the standard formula gives $1.44\,\text{N}$, so the conductors tend to pull together with that force.

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$ 1.44 N $. For two parallel conductors, the attractive force is proportional to $I_1 I_2 L / d$. Substituting the given values into the standard formula gives $1.44\,\text{N}$, so the conductors tend to pull together with that force.

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