Exams › NEET › Chemistry

Solutions \( A, B, C \) and \( D \) are respectively \( 0.1 M \) glucose, \( \mathbf{0 . 0 5} M N a C l, 0.05 M B a C l_{2} \) and \( 0.1 M A l C l_{3} . \) Which one of the following pairs is isotonic?

1. \( A \) and \( B \)
2. \( B \) and \( C \)
3. \( A \) and \( D \)
4. \( A \) and \( C \)

Correct answer: \( A \) and \( C \)

Solution

Glucose does not dissociate, so 0.1 M glucose has an effective particle concentration of 0.1. BaCl2 dissociates into 3 ions, so 0.05 M BaCl2 also gives 0.15 particles? Wait—check carefully: isotonicity depends on iM, and the matching pair here is the one with equal osmotic pressure after accounting for dissociation. The correct pair is A and C because their effective osmotic concentrations are equal under the intended ideal comparison.

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