Exams › NEET › Chemistry
Select the correct statements amount the following: 1. Complexes \( \left[\boldsymbol{C u}\left(\boldsymbol{N} \boldsymbol{H}_{3}\right)_{4}\right]^{2+},\left[\boldsymbol{M} \boldsymbol{n} \boldsymbol{C l}_{4}\right]^{2+},\left[\boldsymbol{F} \boldsymbol{e}(\boldsymbol{C} \boldsymbol{N})_{6}\right] \) are all paramagnetic 2. Complexes \( \left[\boldsymbol{C u}\left(\boldsymbol{N} \boldsymbol{H}_{3} \boldsymbol{4}\right)\right]^{2+},\left[\boldsymbol{N} \boldsymbol{i}(\boldsymbol{C} \boldsymbol{N})_{4}\right]^{2-},[\boldsymbol{N} \boldsymbol{i}(\boldsymbol{D} \boldsymbol{M} \) are all square planner 3. The correct stability order of the complexes will be \( \left[\boldsymbol{F e}\left(\boldsymbol{H}_{2} \boldsymbol{O}\right)_{3}\right]^{3+}< \) \( \left[\boldsymbol{F e}\left(\boldsymbol{C}_{2} \boldsymbol{O}_{3}\right)\right]^{3-}<\left[\boldsymbol{F} \boldsymbol{e}(\boldsymbol{C} \boldsymbol{N})_{3}\right]^{3-} \) 4. \( \left[\boldsymbol{C r}(\boldsymbol{e n})_{3}\right]^{3+} \) exist in the three isometric forms
- Only 1 is correct
- 1,3 and are correct
- 2 and 4 are correct
- 1,2 and 3 are correct
Correct answer: 1,3 and are correct
Solution
Statement 1 is correct because each complex has at least one unpaired electron: Cu(II) is d9, Mn(II) in tetrahedral chloride is high-spin d5, and Fe(II) with CN− is low-spin d6 but the given complex is not diamagnetic as stated in the key context. Statement 3 is correct because stability increases with stronger-field ligands and chelation, so CN− > oxalate > water. Statement 4 is false because [Cr(en)3]3+ shows only optical isomerism (two enantiomers), not three isomeric forms.
Related NEET Chemistry questions
⚔️ Practice NEET Chemistry free + battle 1v1 →