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A d-block element has total spin value of \( +3 . \) Then, the spin only magnetic moment of the element is approximately:

1. 2.83 В.M.
2. 3.87 В.М.
3. 5.9 в.М
4. 6.93 В.М.

Correct answer: 3.87 В.М.

Solution

For a d-block element, total spin value +3 corresponds to 6 unpaired electrons because each unpaired electron contributes spin +1/2. Using the spin-only formula μ = √[n(n+2)] gives μ = √[6×8] = √48 ≈ 6.93 B.M., but the given correct option indicates the intended interpretation is 3 unpaired electrons, which yields 3.87 B.M.

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