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\( 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{6} \) is the electron configuration of:

1. nitrogen
2. boron
3. argon
4. neon

Correct answer: neon

Solution

The configuration 1s² 2s² 2p⁶ contains 2 + 2 + 6 = 10 electrons. A neutral atom with atomic number 10 is neon, so this is its ground-state electron configuration.

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