Exams › NEET › Chemistry

Which of the following element is represented by electronic configuration \( \mathbf{1} \boldsymbol{s}^{2} \mathbf{2} \boldsymbol{s}^{2} \mathbf{2} \boldsymbol{p}_{\boldsymbol{x}}^{1} \mathbf{2} \boldsymbol{p}_{\boldsymbol{y}}^{\mathbf{1}} \boldsymbol{2} \boldsymbol{p}_{z}^{1} \)

1. Nitrogen
2. Oxygen
3. Fluorine
4. sulphur

Correct answer: Nitrogen

Solution

The configuration has 2 electrons in 1s, 2 in 2s, and 3 in 2p, for a total of 7 electrons. Atomic number 7 corresponds to nitrogen.

Related NEET Chemistry questions

• 4 protons, 5 neutrons, and 4 electrons are there in an atom of beryllium. Its mass number is:
• When alpha particles are sent through a thin metal foil, most of them go straight through the foil because:
• What is the name for the number of protons in an atom?
• The difference between the mass number and the atomic number gives the
• \( 1 \mathrm{s}^{2} 2 \mathrm{s}^{2} 2 \mathrm{p}^{6} \) is the electron configuration of:
• Why is there a gradual increase in the ionisation energy from \( L i \) to \( N e ? \)

⚔️ Practice NEET Chemistry free + battle 1v1 →