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The volume of ethyl alcohol (density \( 1.15 g / c c) \) that has to be added to prepare \( 100 \mathrm{cc} \) of \( 0.5 \mathrm{M} \) ethyl alcohol solution in water is :

1. \( 1.15 c c \)
2. \( 2 c c \)
3. \( 2.15 c c \)
4. 2.30 \( c c \)

Correct answer: 2.30 \( c c \)

Solution

A 0.5 M solution contains 0.5 moles per liter, so 100 cc (0.1 L) needs 0.05 moles of ethyl alcohol. Converting that amount to mass and then dividing by density gives the required volume, which is 2.30 cc.

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