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Calculate the volume occupied by 40 g. of a \( C H_{4} \) at \( \mathrm{S.T.P} \) if its \( \mathrm{V} . \mathrm{D} \). is 8

1. 24 litres
2. 46 litres
3. 34 litres
4. 56 litres

Correct answer: 56 litres

Solution

Vapour density 8 means molar mass = 2 × 8 = 16 g/mol, which matches methane. So 40 g is 40/16 = 2.5 moles, and at STP that occupies 2.5 × 22.4 = 56 L.

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