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Which reaction correctly represents the Hofmann bromamide reaction involving a primary amide (RCONH2) with bromine and potassium hydroxide to produce a primary amine (R-NH2)?
- RCONH2 reacts with Br2 and 4KOH to yield R-NH2, 2KBr, K2CO3, and 2H2O.
- RCONH2 combines with Br2 and 4KOH to form R-NH2, 2KBr, K2CO3, and 2H2O.
- RCONH2 undergoes reaction with Br2 and 4KOH, producing R-NH2, 2KBr, K2CO3, and 2H2O.
- RCONH2 plus Br2 and 4KOH results in R-NH2, 2KBr, K2CO3, and 2H2O.
Correct answer: RCONH2 reacts with Br2 and 4KOH to yield R-NH2, 2KBr, K2CO3, and 2H2O.
Solution
The Hofmann bromamide reaction is a well-known reaction where a primary amide reacts with bromine and a strong base (KOH) to form a primary amine. The given reaction is correct and matches the reaction mechanism.
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