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When acetamide and ethylamine are heated with sodium hydroxide, which reaction correctly represents the process?
- CH3CONH2 reacts to form CH3COONa and NH3.
- CH3CONH2 decomposes into CH3COONa and NH3.
- CH3CONH2 breaks down into CH3COONa and NH3.
- CH3CONH2 undergoes reaction to yield CH3COONa and NH3.
Correct answer: CH3CONH2 reacts to form CH3COONa and NH3.
Solution
Acetamide reacts with NaOH upon heating to produce sodium acetate (CH3COONa) and ammonia (NH3). This reaction is a distinguishing test for amides.
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