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When compound C is heated with bromine in the presence of potassium hydroxide, ethylamine is formed. This indicates that compound C is propanamide, and the precursor organic compound (A) must be propanoic acid. The sequence of reactions is:

1. CH3CH2COOH reacts with NH3 to form compound A.
2. CH3CH2COONH4 undergoes heating to yield compound B.
3. CH3CH2CONH2 reacts with KOH and Br2 in the Hoffmann bromamide reaction to produce CH3CH2NH2 (ethylamine).
4. CH3CH2COOH is the organic compound.

Correct answer: CH3CH2COOH reacts with NH3 to form compound A.

Solution

The reaction sequence involves the conversion of propanoic acid to propanamide, which undergoes Hoffmann bromamide reaction to yield ethylamine. This confirms that the organic compound (A) is propanoic acid.

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