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The correct order regarding the electronegativity of hybrid orbitals of carbon is

1. sp > sp2 > sp3
2. sp > sp3 > sp2
3. sp < sp2 < sp3
4. sp > sp2 < sp3

Correct answer: sp > sp2 > sp3

Solution

The electronegativity of carbon increases with the s-character of the hybrid orbital. Since sp has 50% s-character, sp2 has 33.3%, and sp3 has 25%, the correct order is sp > sp2 > sp3.

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