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For the compound CH3CH=CHCH2CH—CH3 | Br, calculate the total number of stereoisomers considering both geometric isomers due to the double bond and optical isomers from the chiral center.

1. 4
2. 2
3. 3
4. 5

Correct answer: 4

Solution

The molecule has one double bond (C=C) allowing for 2 geometrical isomers (cis and trans) and one chiral carbon, which doubles the count due to optical isomerism. Thus, the total number of stereoisomers is 2 × 2 = 4.

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