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ExamsNEETChemistry

According to the Arrhenius equation, the ratio of rate constants at two temperatures, 400 K and 200 K, is expressed as:

  1. k400/k200 = e^(Ea/RT) * (T2-T1)/(T1*T2)
  2. log(k400/k200) = 0
  3. k400 equals k200
  4. The rate constant at 400 K is 1.6 x 10^6 s^-1

Correct answer: k400/k200 = e^(Ea/RT) * (T2-T1)/(T1*T2)

Solution

The given equation is a correct representation of the Arrhenius equation, which relates the rate constants at two different temperatures to the activation energy and temperature difference.

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