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The stability of a carbanion improves with a higher percentage of 's' character, while electron-donating groups reduce carbanion stability. What is the correct order of stability?

1. C with sp hybridization > C with sp2 hybridization > C with sp3 hybridization
2. Tertiary carbanion > sp2 hybridized CH2
3. Stability of carbanion decreases due to electron-donating groups
4. Stability of carbanion increases due to electron-donating groups

Correct answer: C with sp hybridization > C with sp2 hybridization > C with sp3 hybridization

Solution

Carbanion stability increases with higher 's' character because the negative charge is closer to the nucleus, making it more stable. Thus, the correct order is Csp > Csp2 > Csp3.

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