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Ammonium chloride, being derived from a weak base and a strong acid, has its hydrolysis constant (Kh) determined by which of the following expressions?

1. Kh = Kw divided by Kb
2. Kh = 1 × 10^-14 divided by 1.77 × 10^-5, which equals 5.65 × 10^-10
3. Kh = Kw divided by Kb
4. Kh = 1 × 10^-14 divided by 1.77 × 10^-5, which equals 5.65 × 10^-10

Correct answer: Kh = Kw divided by Kb

Solution

The hydrolysis constant (Kh) for a salt of a weak base and strong acid is given by the formula Kh = Kw / Kb, where Kw is the ionic product of water and Kb is the base dissociation constant.

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