Exams › NEET › Chemistry

In the equilibrium between a solid and its liquid form, which is an endothermic reaction, what happens if the temperature is increased?

1. The equilibrium moves toward the formation of more liquid.
2. The equilibrium moves toward the formation of more solid.
3. The equilibrium remains unchanged.
4. None of the above.

Correct answer: The equilibrium moves toward the formation of more liquid.

Solution

Since the process is endothermic, increasing temperature provides the required heat, favoring the forward reaction (solid to liquid) as per Le Chatelier's principle.

Related NEET Chemistry questions

• A beaker contains a saturated solution of copper(l) chloride. Copper(l) chloride is slightly soluble salt with a solubility product of \( 1.2 \times 10^{-6} \) Which of the following salts when added to the solution would precipitate copper(l) chloride?
• The function of 'buffer solution' is:
• When \( C a(O H)_{2} \) attains solubility equilibrium, the:
• Predict if there will be any precipitate by mixing \( 50 \mathrm{mL} \) of \( 0.01 \mathrm{M} \) NaCl and 50 mL of \( 0.01 \mathrm{M} A g N O_{3} \) solution. The solubility product of \( A g C l \) is \( 1.5 \times \) \( 10^{-10} \)
• Calculate the ratio of \( H C O O^{-} \) and \( F^{-} \) in a mixture of \( 0.2 M \) HCOOH \( \left(K_{a}=\right. \) \( \left.2 \times 10^{-4}\right) \) and \( 0.1 M H F\left(K_{a}=6.6 \times\right. \) \( \left.10^{-4}\right) \)
• What is the [OH⁻] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)₂?

⚔️ Practice NEET Chemistry free + battle 1v1 →