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Determine the spacing between atomic planes (d) for a crystal where the Bragg diffraction order (n) is 2, the wavelength of incident light (λ) is 1 Å, and the diffraction angle (θ) is 60°.

1. 1.15 Å
2. 1.73 Å
3. 2.00 Å
4. 0.87 Å

Correct answer: 1.73 Å

Solution

Using Bragg's equation, nλ = 2d sinθ, we substitute n = 2, λ = 1 Å, and θ = 60°. Solving for d, we get d = (nλ) / (2 sinθ) = (2 × 1) / (2 × √3/2) = 1.73 Å.

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