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Electronegativity decreases in order F > Cl > Br and hence –I effect also decreases in the same order. Therefore, the correct option is:

1. [FCH2COOH > ClCH2COOH > BrCH2COOH > CH3COOH]
2. [ClCH2COOH > FCH2COOH > BrCH2COOH > CH3COOH]
3. [BrCH2COOH > ClCH2COOH > FCH2COOH > CH3COOH]
4. [CH3COOH > FCH2COOH > ClCH2COOH > BrCH2COOH]

Correct answer: [FCH2COOH > ClCH2COOH > BrCH2COOH > CH3COOH]

Solution

Electronegativity of halogens decreases in the order F > Cl > Br, so the -I (inductive) effect also decreases in the same order. This makes FCH2COOH the strongest acid, followed by ClCH2COOH, BrCH2COOH, and CH3COOH.

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