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The halogenated fatty acids are much stronger acids than the parent fatty acid and moreover the acidity among the halogenated fatty acid increases almost proportionately with the increase in electronegativity of the halogen present. Further, formic acid having no alkyl group is more acidic than acetic acid.

1. CF3COOH > CCl3COOH > HCOOH > CH3COOH (Ka order)
2. CH3COOH > CF3COOH > HCOOH > CCl3COOH
3. HCOOH > CH3COOH > CF3COOH > CCl3COOH
4. CCl3COOH > CF3COOH > CH3COOH > HCOOH

Correct answer: CF3COOH > CCl3COOH > HCOOH > CH3COOH (Ka order)

Solution

The acidity of halogenated fatty acids increases with the electronegativity of the halogen due to the inductive effect, which stabilizes the conjugate base. Formic acid is more acidic than acetic acid because it lacks an electron-donating alkyl group. Thus, the correct Ka order is CF3COOH > CCl3COOH > HCOOH > CH3COOH.

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