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Acetaldehyde reacts with semicarbazide and forms semicarbazone. Its structure is:

1. CH3CH=NNHCON=CHCH3
2. CH3CH=NNHCONH2
3. CH3CH=N—N—CONH2
4. CH3CH=N—CONNH2

Correct answer: CH3CH=NNHCONH2

Solution

Semicarbazide reacts with the carbonyl group of acetaldehyde to form a semicarbazone, where the C=O group is replaced by a C=N bond attached to the semicarbazide moiety. The correct structure is CH3CH=NNHCONH2.

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