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An ester is boiled with KOH. The product is cooled and acidified with concentrated HCl. A white crystalline acid separates. The ester is

1. Methyl acetate
2. Ethyl acetate
3. Ethyl formate
4. Ethyl benzoate

Correct answer: Ethyl benzoate

Solution

When ethyl benzoate is hydrolyzed with KOH, it forms benzoic acid and ethanol. Upon acidification, benzoic acid precipitates as a white crystalline solid due to its low solubility in water.

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