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An organic compound ‘A’ on treatment with NH₃ gives ‘B’ which on heating gives ‘C’. ‘C’ when treated with Br₂ in the presence of KOH produces ethylamine. Compound ‘A’ is:
- (a) CH₃COOH
- (b) CH₃CH₂CH₂COOH
- (c) CH₃–CHCOOH
| CH₃
- (d) CH₃CH₂COOH
Correct answer: (d) CH₃CH₂COOH
Solution
Compound 'A' is CH₃CH₂COOH (propanoic acid). It reacts with NH₃ to form CH₃CH₂CONH₂ (amide 'B'), which on heating gives CH₃CH₂CN ('C'). When 'C' undergoes Hoffmann bromamide degradation with Br₂ and KOH, it produces ethylamine (CH₃CH₂NH₂).
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