Exams › NEET › Chemistry

In the reaction CH3CHO + HCN → CH3CH(OH)CN →(H2O/H+)→ CH3CH(OH)COOH, an asymmetric centre is generated. The acid obtained would be

1. (a) 20% D + 80% L-isomer
2. (b) D-isomer
3. (c) L-isomer
4. (d) 50% D + 50% L-isomer

Correct answer: (d) 50% D + 50% L-isomer

Solution

The reaction involves the formation of a chiral center at the carbon atom attached to the hydroxyl group and cyanide group. Since the reaction proceeds via a planar intermediate, equal probabilities exist for the formation of both enantiomers, resulting in a racemic mixture (50% D and 50% L).

Related NEET Chemistry questions

• The structure of isobutyl group in an organic compound is:
• The general molecular formula, which represents the homologous series of alkanols is
• The correct order regarding the electronegativity of hybrid orbitals of carbon is
• The number of possible isomers of the compound with molecular formula C4H8O is
• Tautomerism will be exhibited by
• Isomers of a substance must have the same

⚔️ Practice NEET Chemistry free + battle 1v1 →