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Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is:

1. CH3CH2CH2C=CH3
2. CH3CH2CH2C=CH2CH2CH3
3. CH3CH2CH2C=CH2CH2CH3
4. CH3CH2CH2C=CH2CH2CH3

Correct answer: CH3CH2CH2C=CH2CH2CH3

Solution

When acetone reacts with excess ethanol in the presence of HCl, an acetal is formed. The product is a diethyl acetal of acetone.

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