Exams › NEET › Chemistry
The enolic form of ethyl acetoacetate as below has:
- 16 sigma bonds and 1 pi-bond
- 9 sigma bonds and 2 pi-bonds
- 9 sigma bonds and 1 pi-bond
- 18 sigma bonds and 2 pi-bonds
Correct answer: 16 sigma bonds and 1 pi-bond
Solution
The enolic form of ethyl acetoacetate contains 16 sigma bonds (from single bonds) and 1 pi-bond (from the C=C double bond in the enol group). Counting all bonds confirms this.
Related NEET Chemistry questions
⚔️ Practice NEET Chemistry free + battle 1v1 →