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Diborane \( \left(B_{2} H_{6}\right) \) reacts independently with \( O_{2} \) and \( H_{2} O \) to produce :

1. \( H B O_{2} \) and \( H_{3} B O_{3} \)
2. \( H_{3} B O_{3} \) and \( B_{2} O_{3} \)
3. \( B_{2} O_{3} \) and \( H_{3} B O_{3} \)
4. \( B_{2} O_{3} \) and \( \left[B H_{4}\right]^{-} \)

Correct answer: \( H_{3} B O_{3} \) and \( B_{2} O_{3} \)

Solution

Diborane burns in oxygen to form boron(III) oxide, while hydrolysis with water produces boric acid. So the two independent reactions give B2O3 and H3BO3, respectively.

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